Can you explain this answer? defined & explained in the simplest way possible. The vapor pressure of water (in torr) for this aqueous solution is :a)7.6b)76.0c)752.4d)759.0Correct answer is option 'C'. Here you can find the meaning of 18 g glucose (C6H12O6) is added to 178.2 g water. Hence, the correct option is (c) 752.4 torr. Therefore, the vapor pressure of water (in torr) for this aqueous solution is 23.52 torr. ![]() Therefore, the vapor pressure of the solution is equal to the vapor pressure of water, which is 23.52 torr. The vapor pressure of glucose can be neglected as its mole fraction is very low. Xglucose = Moles of glucose / (Moles of glucose + Moles of water) The mole fraction of glucose in the solution is given by: The vapor pressure of the solution is the sum of the partial pressures of all the components in the solution. Step 4: Calculation of vapor pressure of the solution Where P0 is the vapor pressure of pure water and Xwater is the mole fraction of water in the solution.Īt 25☌, the vapor pressure of pure water is 23.76 torr. Step 3: Calculation of vapor pressure of waterĪccording to Raoult's law, the vapor pressure of water (P) in the solution is given by: Mole fraction of water = Moles of water / (Moles of glucose + Moles of water) Step 2: Calculation of mole fraction of water Moles of water = Mass of water / Molar mass of water Moles of glucose = Mass of glucose / Molar mass of glucose ![]() Step 1: Calculation of moles of glucose and water This is a question based on the concept of Raoult's law which states that the vapor pressure of a solution is directly proportional to the mole fraction of the solvent in the solution.
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